What is the derivative of $sqrt(7x)$ ?

Question

12819 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-16T09:58:59

$7/(2sqrt(7x))$

rewrite the function as: $sqrt(7x) = (7x )^(1/2 )$

applying the 'chain rule' : $1/2 (7x)^(-1/2 ). d/dx (7x)$

= $1/2 (7x)^(-1/2)(7) = 7/(2sqrt(7x))$

Answer 2 · 2016-01-16T16:31:17

$sqrt7/(2sqrtx)$ , or, if you disapprove of radicals in the denominator, it is $sqrt(7x)/(2x)$

$sqrt(7x) = sqrt7sqrtx$ and $d/dx(sqrtx)=1/(2sqrtx)$ .

Therefore,

$d/dx(sqrt(7x)) = sqrt7d/dx(sqrtx) = sqrt7(1/(2sqrtx)) = sqrt7/(2sqrtx)$ .

Eliminate the square root from the denominator if necessary.

What is the derivative of sqrt(7x)sqrt(7x)?