What is the derivative of $sqrt(8x+1)$ ?

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Answer 1 · 2016-03-28T01:55:51

$d/dxsqrt(8x+1) =4/sqrt(8x+1)$

Applying the chain rule:

$d/dxsqrt(8x+1) = d/dx(8x+1)^(1/2)$

$= 1/2(8x+1)^(-1/2)*(d/dx(8x+1))$

$=1/(2sqrt(8x+1))*8$

$=4/sqrt(8x+1)$

What is the derivative of sqrt(8x+1)sqrt(8x+1)?