What is the derivative of T(w)=cot^3(3w+1)? Calculus Basic Differentiation Rules Chain Rule 1 Answer maganbhai P. Mar 27, 2018 T^'(w)=-9cot^2(3w+1)csc^2(3w+1) Explanation: We know that, color(red)((1)d/(dx)(x^n)=nx^(n-1) color(red)((2)d/(dx)(cotx)=-csc^2x Here, T(w)=cot^3(3w+1)=(cot(3w+1))^3 Diff.w.r.t. 'w' T^'(w)=3(cot(3w+1))^2d/(dw)((cot(3w+1))...toApply(1) =3cot^2(3w+1)(-csc^2(3w+1))d/(dw)(3w+1).toApply(2) =-3cot^2(3w+1)csc^2(3w+1)(3) =-9cot^2(3w+1)csc^2(3w+1) Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 4000 views around the world You can reuse this answer Creative Commons License