What is the derivative of $tan^3(x^4)$ ?

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Answer 1 · 2018-04-18T08:22:40

$dy/dx=12tan^2(x^4)sec^2(x^4)x^3$

$y=tan^3(x^4)$

$dy/dx=d/dx[tan^3(x^4)]=3tan^(3-1)(x^4)*d/dx[tan(x^4)]=3tan^2(x^4)(sec^2(x^4)d/dx[x^4])=12tan^2(x^4)sec^2(x^4)x^3$

What is the derivative of tan^3(x^4) tan^3(x^4)?