What is the derivative of this function $y=29/4cot^-1((2x)/3)$ ?

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Answer 1 · 2018-05-13T11:32:22

the answer
$y'=-(58)/[12[1+((2x)/3)^2]]$

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$y=cot^-1(x)$

$y'=[-1*x']/(1+(x)^2)$

$y=29/4cot^-1((2x)/3)$

$y'=29/4*-(2/3)/[1+((2x)/3)^2]$

$y'=-(58/12)/[1+((2x)/3)^2]$

$y'=-(58)/[12[1+((2x)/3)^2]]$

What is the derivative of this function y=29/4cot^-1((2x)/3)y=29/4cot^-1((2x)/3)?