What is the derivative of this function $y=cos^-1(1-3x^2)$ ?

Question

4436 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-03T23:29:26

$= pm (6)/(sqrt( 6 - 9x^2))$

$cos y = 1 - 3x^2$

$- sin y \ y' = -6x$

$y' = (6x)/(sin y )$

$= (6x)/(sqrt(1- cos^2 y) )$

$= (6x)/(sqrt(1- (1 - 3x^2)^2) )$

$= (6x)/(sqrt(1- (1 + 9x^4- 6 x^2)) )$

$= (6x)/(sqrt( - 9x^4+ 6 x^2))$

$= (6x)/(sqrt( 6 x^2 - 9x^4))$

$= pm (6)/(sqrt( 6 - 9x^2))$

What is the derivative of this function y=cos^-1(1-3x^2)y=cos^-1(1-3x^2)?