What is the derivative of $y = 10^(1-x^2)$ ?

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Answer 1 · 2016-06-21T08:28:22

$y' = -2\ln (10) \ x \ 10^{1-x^2}$ x

take natural logs

$\ln y = \ln (10^(1- x^2)) = (1- x^2) \ln (10)$

$\frac{1}{y} y' = - 2x \ln( 10)$

$y' = - 2x \ln 10 \times y = -2\ln (10) \ x \ 10^{1-x^2}$

What is the derivative of y = 10^(1-x^2)y = 10^(1-x^2)?