What is the derivative of $y = 4 {sec}^{2} (x)$ $y=4 sec ^2(x)$ ?

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Answer 1 · 2014-08-15T13:58:57

$y'=8sec^2(x)tan(x)$

Explanation :

let's start with general function, $y=(f(x))^2$

differentiating with respect to $x$ Using Chain Rule,

$y'=2*f(x)*f'(x)$

Similarly following for given problem, yields

$y= 4*sec^2(x)$

$y'=4*2*sec(x)*sec(x)tan(x)$

$y'=8sec^2(x)tan(x)$

What is the derivative of y=4 sec ^2(x)y=4sec2(x)y=4 sec ^2(x)?