What is the derivative of $y = {sec}^{2} (x)$ $y=sec^2(x)$ ?

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Answer 1 · 2014-09-21T23:54:53

We need to use the chain rule

$y = {sec}^{2} (x)$ $y=sec^2(x)$

Let $u = sec (x)$ $u=sec(x)$

$u'=sec(x)tan(x)$

$y=u^2$

$y'=2u*u'$

$y'=2sec(x)* sec(x)tan(x)=2sec^2(x)tan(x)$

What is the derivative of y=sec^2(x)y=sec2(x)y=sec^2(x)?