What is the derivative of $y = arccos (x^{2})$ $y=arccos(x^2 )$ ?

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Answer 1 · 2014-09-04T16:47:08

By Chain Rule, we can find
$y'=-{2x}/{sqrt{1-x^4}}$ .

Recall the chain rule $[f(g(x))]'=f'(g(x))cdot g'(x)$ , and
$(arccos x)'=-1/sqrt{1-x^2}$ .

Now, let us take the derivative of the posted function.
By Chain Rule,
$y'=-1/sqrt{1-(x^2)^2}cdot2x=-{2x}/sqrt{1-x^4}$

What is the derivative of y=arccos(x^2 )y=arccos(x2)y=arccos(x^2 )?