What is the derivative of $y=e^((2x)/3)$ ?

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Answer 1 · 2015-08-20T20:12:45

$y' = 2/3 e^((2x)/3)$

$d/dx(e^u) = e^u (du)/dx$ $" "" "$ (Chain rule)

In this case $u = (2x)/3$ so $(du)/dx = 2/3$

$d/dx(e^((2x)/3)) = e^((2x)/3) * 2/3 = 2/3 e^((2x)/3)$

What is the derivative of y=e^((2x)/3) y=e^((2x)/3)?