What is the derivative of $y = - e^{x^{2} + x - 3}$ $y= -e^(x^2+x-3)$ ?

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Answer 1 · 2015-11-15T05:20:57

$- (2 x + 1) e^{x^{2} + x - 3}$ $-(2x+1)e^(x^2+x-3)$

According to the Chain Rule, the derivative of $e^{u}$ $e^u$ is equivalent to $u'e^u$ .

So, we can say that $y'=-(d)/(dx)[x^2+x-3]*e^(x^2+x-3)$ .

We can calculate that $d/(dx)[x^2+x-3]=2x+1$ .

Now, we plug the value of the derivative back into the equation we found from the chain rule to determine that $color(red)(y'=-(2x+1)e^(x^2+x-3)$

What is the derivative of y= -e^(x^2+x-3) y=−ex2+x−3y= -e^(x^2+x-3) ?