What is the derivative of y= ln(1 + e^(2x))? Calculus Basic Differentiation Rules Chain Rule 1 Answer Konstantinos Michailidis Dec 26, 2015 The derivative is d(ln(1+e^(2x)))/dx=((1+e^(2x))')/(1+e^(2x))=2*e^(2x)/(1+e^(2x) Finally dy/dx=(2*e^(2x))/(1+e^(2x)) Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 2840 views around the world You can reuse this answer Creative Commons License