What is the derivative of $y= ln(2x)/x^2$ ?

Question

3805 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-16T01:32:47

$dy/dx=(1-2ln(2x))/x^2$

$dy/dx=(2(1/(2x))(x^2)-(ln(2x)(2x)))/x^4$

Simplify:

$dy/dx=(x-ln(2x)(2x))/x^4$

Take out a $x$ from the numerator and denominator:

$dy/dx=(1-2ln(2x))/x^2$

What is the derivative of y= ln(2x)/x^2 y= ln(2x)/x^2?