What is the derivative of $y= log (6x-2)$ ?

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Answer 1 · 2015-08-14T03:10:03

$dy/dx=6/(ln(10)(6x-2))$

Assuming $log(6x-2)=log_{10}(6x-2)$ , the Chain Rule and the fact that $d/dx(log_{10}(x))=1/(ln(10)x)$ imply that

$dy/dx=6/(ln(10)(6x-2))$ when $y=log(6x-2)$ .

What is the derivative of y= log (6x-2)y= log (6x-2)?