What is the derivative of y=pi^x+x^pi? Calculus Basic Differentiation Rules Chain Rule 1 Answer Alan N. Sep 29, 2016 y' = ln(pi)*x^pi + pix^(pi-1) Explanation: y=pi^x+x^pi Let's split this into two: y = y_1=pi^x plus y_2 =x^pi lny_1= xlnpi 1/y_1 y_1' = lnpi By Implicit differentiation :.y_1' = lnpi * x^pi y_2' = pix^(pi-1) By Power rule Now: y' = y_1' + y_2' Hence: y' = ln(pi)*x^pi + pix^(pi-1) Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 6792 views around the world You can reuse this answer Creative Commons License