What is the derivative of $y=sqrt(tan^-1 x)$ ?

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Answer 1 · 2016-03-16T18:38:07

It is

$dy/dx=1/2*[arctanx]^(-1/2)*(d(arctanx)/dx)= 1/2*[arctanx]^(-1/2)*[1/(1+x^2)]= 1/2*[1/[sqrt(arctanx)*(1+x^2)]]$

What is the derivative of y=sqrt(tan^-1 x)y=sqrt(tan^-1 x)?