What is the exact value of #(7pi)/12#?

Question

I got #(sqrt3+1)/(1-sqrt3)#

Is this right? I feel like I did something wrong...

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Answer 1 · 2017-11-27T18:23:56

See below.

Not sure what you are trying to do here.

#(sqrt(3)+1)/(1-sqrt(3))<0#

You can't find an exact value for #(7pi)/12#. #pi# is an irrational number and can't be written in terms of other irrational or rational numbers.