What is the excluded value for y=1/(x+3)y=1x+3?

1 Answer
Jim G.
Aug 15, 2017

x=-3x=−3

Explanation:

"the denominator of y cannot be zero as this would make"the denominator of y cannot be zero as this would make
"y undefined. Equating the denominator to zero and"y undefined. Equating the denominator to zero and
"solving gives the value that x cannot be"solving gives the value that x cannot be

"solve "x+3=0rArrx=-3larrcolor(red)" excluded value"solve x+3=0⇒x=−3← excluded value

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