What is the general solution of #dy/dx = ysinx#?

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Answer 1 · 2017-08-18T15:15:01

THe solution is #y=e^(-cosx+C)#

This is a first order differential equation of the form #N(y)dy=M(x)dx#

#dy/dx=ysinx#

#dy/y=sinxdx#

Integrating both sides

#intdy/y=intsinxdx#

#lny=-cosx+C#

#y=e^(-cosx+C)#