What is the integral of $int e^((x^2)) dx$ ?

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Answer 1 · 2016-11-04T15:52:02

$=C+x+(1/3)x^3/(1!)+(1/5)x^5/(2!)+(1/7)x^7/(3!)+...$

Use $e^X=1+X+X^3/(2!)+X^3/(3!)|..$

$inte^(x^2) dx$

$=int (1+x^2/(1)+x^4/(2!)+x^6/(3!)+...)dx$

$=C+x+(1/3)x^3/(1!)+(1/5)x^5/(2!)+(1/7)x^7/(3!)+...$

What is the integral of int e^((x^2)) dx int e^((x^2)) dx ?