What is the Integral of (x+1)/x dx?

1 Answer
Jun 4, 2015

Not many people realize this, but the key to doing this is to separate it using the additive properties of integrals.

int (x+1)/xdx

= int cancel(x/x)dx + int 1/xdx

= int dx + int 1/xdx

= color(blue)(x + ln|x| + C)

where you'll have to remember that the integral of 1/u((du)/(dx)) is ln|u|. You'll see it a lot more later.