What is the mass of $25.0$ $cm^3$ of gold?

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Answer 1 · 2016-02-23T18:15:23

Gold has a density, $rho$ $=$ $19.32$ $g*cm^-3$ . This very high density allows ALLUVIAL gold to be panned....i.e. separated by mass...

For mass, we simply take the product, $"volume "xx" density"$ , i.e. $25.0*cancel(cm^3)xx19.32*g*cancel(cm^-3)$ $=$ $?? g$

What is the mass of 25.025.0 cm^3cm^3 of gold?