What is the maximum value that the graph of y= x^2 -4x? Calculus Graphing with the First Derivative Identifying Stationary Points (Critical Points) for a Function 1 Answer Jim H Oct 6, 2016 There is no maximum. Explanation: As x increases without bound, x^2-4x also increases without bound. (Another way of saying this is: lim_(xrarroo)(x^2-4x) = oo.) That means there is no upper bound and no maximum. Answer link Related questions How do you find the stationary points of a curve? How do you find the stationary points of a function? How many stationary points can a cubic function have? How do you find the stationary points of the function y=x^2+6x+1? How do you find the stationary points of the function y=cos(x)? How do I find all the critical points of f(x)=(x-1)^2? Let h(x) = e^(-x) + kx, where k is any constant. For what value(s) of k does h have... How do you find the critical points for f(x)=8x^3+2x^2-5x+3? How do you find values of k for which there are no critical points if h(x)=e^(-x)+kx where k... How do you determine critical points for any polynomial? See all questions in Identifying Stationary Points (Critical Points) for a Function Impact of this question 1664 views around the world You can reuse this answer Creative Commons License