What is the mBAC=?

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Answer 1 · 2018-05-14T18:10:29

${82.1}^{\circ}$ $82.1^@$

AB=10 AD=4 and BD=6

AC=10 AE=8 and CE=2

Using triangle ADE, $\frac{sin 28}{4} = \frac{sin A ˆ D E}{8}$ $(sin 28)/4=(sin AhatDE)/8$

So $8 \times \frac{sin 28}{4} = sin A ˆ D E$ $8 xx (sin 28)/4=sin AhatDE$

$2 \times sin 28 = sin A ˆ D E$ $2xx sin 28 = sin AhatDE$

$A ˆ D E = {sin}^{- 1} 0.9389431256$ $AhatDE = sin^(-1) 0.9389431256$

$A ˆ D E = 69.87481894$ $AhatDE=69.87481894$

180-28-69.9=82.1