What is the moment of inertia of a pendulum with a mass of #5 kg# that is #13 m# from the pivot?

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Answer 1 · 2017-04-06T13:03:33

The moment of inertia is

#I=mr^2#

The mass is #=5kg#

The radius is #=13m#

The moment of inertia is

#I=5*13^2=845kgm^2#