Question

What is the moment of inertia of a pendulum with a mass of `7 kg` that is `7 m` from the pivot?

Answer 1

I got `343 \ "kg"*"m"^2`.

Explanation:

The moment of inertia of a simple pendulum is given by

`I=mr^2`, where `m` is the mass of the pendulum in kilograms, and `r` is the distance of the pendulum from the pivot in meters.

So here, we got `m=7 \ "kg", r=7 \ "m"`.

`:.I=7 \ "kg"*49 \ "m"^2`

`=343 \ "kg"*"m"^2`