What is the moment of inertia of a pendulum with a mass of #7 kg# that is #9 m# from the pivot?

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Answer 1 · 2018-03-30T03:28:42

#567 \ "kg m"^2#

The moment of inertia of pendulum is given by:

#I=mr^2#

#m# is the mass in kilograms

#r# is the distance from the pivot in meters

So here, we get:

#I=7 \ "kg"*(9 \ "m")^2#

#=7 \ "kg"*81 \ "m"^2#

#=567 \ "kg m"^2#