Question

What is the moment of inertia of a rod with a mass of `4 kg` and length of `15 m` that is spinning around its center?

Answer 1

`I=1/12*4kg*(15m)^2 = 225/3 kg*m^2`

Explanation:

Moment of Inertia, `I =1/12 ml^2`
`m=4kg; l=15m`
`I=1/12*4kg*(15m)^2 = 225/3 kg*m^2`