Question

What is the moment of inertia of a rod with a mass of `6 kg` and length of `25 m` that is spinning around its center?

Answer 1

The answer is `=12.5 kgm^2`

Explanation:

The moment of inertia of a rod (spinning around its center) is

`I=1/12*mL^2`

`m=6 kg`

`L=25 m`

Therefore,

`I=1/12*6*25=12.5 kgm^2`