What is the oxidation state of each element in #Mn(CrO_4)#?

1 Answer
anor277
Jun 14, 2016

#Mn(II+), Cr(VI+), O(-II)#.

Explanation:

The typical oxidation state of oxygen is #-II#, and it is here. Manganese typically takes a #+II# oxidation state. This leaves chromium to balance the oxidation states (the oxidation states must sum to zero in a neutral compound). Thus #2-8+Cr_"oxidation state"=O#.

We have #Cr(VI+)#, which is its maximum oxidation number

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