Question

What is the percent solution if 25mL of `CH_"3"OH` is DILUTED WITH 150mL with water?

Answer 1

Well, we would like to think that the volumes are additive....

Explanation:

And thus `"% by volume"`....

`="Volume of methanol"/"Volume of methanol + volume of water"xx100%=`

`(25*mL)/(150*mL+25*mL)xx100%=??*%`