Question

What is the period of `f(t)=sin( 2 t -pi/4)`?

Answer 1

`Period=pi`

Explanation:

Comparing with the General sine wave form`(f(t)=A*sin(B*x+C)+D)` Where A is amplitude; Period is `(2*pi)/B` ; Phase Shift is `-C/B` and Vertical shift is `D`, Here `A=1; B=2; C=-pi/4 ; D=0` So Period=`(2*pi)/2 or Period=pi` [answer] graph{sin(2x-pi/4) [-10, 10, -5, 5]}