What is the slope and y-intercept of the line #y =1/4 x + 2#?
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"How do I change #int_0^1int_0^sqrt(1-x^2)int_sqrt(x^2+y^2)^sqrt(2-x^2-y^2)xydzdydx# to cylindrical or spherical coordinates?"
1 Answer
May 29, 2017
Slope is 0.25 and intercept is 2
Explanation:
Slope of this line is coefficient of x (which is 1/4)
y intercept is 2. Because when
graph{(0.25x) + 2 [-10, 10, -5, 5]}
When y is zero, your x is -8.
