What is the slope of a line that is perpendicular to $2 x - 5 y = 3$ $2x-5y=3$ ?

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Answer 1 · 2017-11-06T15:05:05

$- \frac{5}{2}$ $-5/2$

The slope of the given line can be determined by writing the equation in its slope-intercept form.

$2 x - 5 y = 3$ $2x-5y=3$

$- 5 y = 3 - 2 x$ $-5y=3-2x$

$y = - \frac{3}{5} + \frac{2 x}{5}$ $y = -3/5 + (2x)/5$
$y = \frac{2}{5} x - \frac{3}{5}$ $y=2/5x - 3/5$

The slope of the given line is $\frac{2}{5}$ $2/5$

The slope of the line perpendicular to the given line is equal to the negative reciprocal of the slope of the given line.

negative reciprocal of $n$ $n$ = $\frac{- 1}{n}$ $(-1)/n$

negative reciprocal of $\frac{2}{5} = \frac{- 1}{\frac{2}{5}}$ $2/5 = (-1)/(2/5)$
$- \frac{1}{1} \div \frac{2}{5}$ $-1/1 div 2/5$

$= - \frac{1}{1} \cdot \frac{5}{2}$ $= -1/1 * 5/2$

$- \frac{5}{2}$ $-5/2$

What is the slope of a line that is perpendicular to 2x−5y=32x-5y=3?