What is the slope of a line that is perpendicular to $3 y + 2 x = 6$ $3y+2x=6$ ?

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What is the slope of a line that is perpendicular to $3 y + 2 x = 6$ $3y+2x=6$ ?

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Answer 1 · 2018-04-02T11:34:40

$m = \frac{3}{2}$ $m=3/2$

Explanation:

A line is a negative inverse of it perpendicular line.
This means m(1) $m (1) = - \frac{1}{m (2)}$ $m(1)=-1/(m(2))$

Through manipulation of the equation we change it to $y = - \frac{2}{3} x + \frac{6}{3}$ $y=-2/3x+6/3$
The $- \frac{2}{3}$ $-2/3$ infront of the represents the slope of the line.
Using idea from earlier we flip the gradient and times it by -1.
$- \frac{2}{3} = - \frac{1}{m}$ $-2/3=-1/m$ (cross multiply)

$3 m = 2$ $3m=2$ (divide the 3)

$m = \frac{3}{2}$ $m=3/2$

Answer 2 · 2018-04-02T11:44:42

$\frac{3}{2}$ $3/2$

Explanation:

If two lines are perpendicular then the result of multiplying the two gradients together always equals -1

Rearrange the equation to find the gradient:

$3 y + 2 x = 6$ $3y +2x = 6$

$\Rightarrow$ $=>$ $3 y = - 2 x + 6$ $3y = -2x +6$

$\Rightarrow$ $=>$ $y = - \frac{2}{3} x + 2$ $y = -2/3x +2$

Gradient = $- \frac{2}{3}$ $-2/3$ the reciprocal is $\frac{3}{2}$ $3/2$

$- \frac{2}{3} \times \frac{3}{2} = - 1$ $-2/3 xx 3/2 = -1$

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What is the slope of a line that is perpendicular to $3 y + 2 x = 6$ $3y+2x=6$ ?

2 Answers

Explanation:

Explanation:

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