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What is the slope of $f (x) = - x e^{x} - x^{2}$ $f(x)=-xe^x-x^2$ at $x = 1$ $x=1$ ?

1 Answer

A. S. Adikesavan

Mar 2, 2016

$-$ $-$ 2 ( 1 + e ), e = 2.718281828....

Explanation:

$\frac{d}{d x}$ $d/dx$ f(x) = $-$ $-$ e^x $-$ $-$ xe^x $-$ $-$ 2x

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