What is the slope of the line perpendicular to $y=-3/4x+11$ ?

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Answer 1 · 2018-04-10T03:15:26

$4/3$

First, identify your slope. The function you presented follows $y=mx+b$ wherein $m$ is the slope, which is $-3/4$ .

The slope of the line perpendicular to a given slope is the negative reciprocal of it.

That is, if we have a slope $m_1$ , and a slope perpendicular to it, $m_2$ , then, $m_1*m_2=-1$

In your case, $4/3*-3/4=-1$ , thus the answer $4/3$ .

What is the slope of the line perpendicular to y=-3/4x+11 y=-3/4x+11 ?