What is the slope perpendicular to the line -6x -8y = 8?

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Answer 1 · 2017-09-11T14:02:08

$\frac{4}{3}$ $4/3$

We have:

$- 6 x - 8 y = 8$ $-6x -8y = 8$

We put this into standard form $y = m x + c$ $y=mx+c$ by rearranging:

$8 y = - 6 x - 8$ $8y = -6x- 8$
$:. 4y = -3x- 4$
$:. y = -3/4x- 1$

So the slope of the given line is $m=-3/4$

And, the slope of a perpendicular line is:

$m_p = -1/m = 4/3$