What is the solution set of $\frac{1}{2} {log}_{7} x = 4 {log}_{7} 2 - {log}_{7} 4$ $1/2 log_(7)x = 4 log_(7)2 - log_(7)4$ ?

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Answer 1 · 2018-08-11T19:10:21

${16}$ ${16}$

${log}_{7} x^{\frac{1}{2}} = {log}_{7} \frac{2^{4}}{4}$ $log_7 x^{1/2} = log_7 frac{2^4}{4}$

$\sqrt{x} = \frac{16}{4}$ $sqrt x = 16/4$

$x = 4^{2}$ $x = 4^2$

What is the solution set of 1/2 log_(7)x = 4 log_(7)2 - log_(7)412log7x=4log72−log741/2 log_(7)x = 4 log_(7)2 - log_(7)4?