What is the solution set of $4[9^(x-1)] = 108$ ?

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Answer 1 · 2015-05-10T21:32:18

Take 4 to the right:
$9^(x-1)=108/4=27$
$9^(x-1)=3^3$
But $9=3^2$ so:
$3^(2(x-1))=3^3$
And:
$2(x-1)=3$
$2x-2=3$
$x=5/2$

What is the solution set of 4[9^(x-1)] = 1084[9^(x-1)] = 108?