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What is the speed of the ball at point B? (Physics)

1 Answer

May 22, 2018

See below

Explanation:

${(T + U)}_{A} = {(T + U)}_{B} = 25$ $(T+U)_A = (T+U)_B = 25$

$U_{B} = 0 \Rightarrow T_{B} = 25 = \frac{1}{2} m v^{2}$ $U _B = 0 implies T_B = 25 = 1/2 m v^2$

$m = 2$ $m = 2$

$speed = | v | = \sqrt{\frac{2 \cdot 25}{2}} = 5 m/s$ $"speed " = abs v = sqrt((2*25)/2) = 5" m/s"$

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