What is the standard form of $f (x) = (2 x - 3) {(x - 2)}^{2} + 4 x - 5$ $f(x)=(2x-3)(x-2)^2+4x-5$ ?

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Answer 1 · 2017-09-23T11:57:34

The standard form is $f (x) = 2 x^{3} - 11 x^{2} + 24 x - 17$ $f(x) = 2x^3-11x^2+24x-17$

$f (x) = (2 x - 3) {(x - 2)}^{2} + 4 x - 5$ $f(x) = (2x-3)(x-2)^2 +4x -5$ or

$f (x) = (2 x - 3) (x^{2} - 4 x + 4) + 4 x - 5$ $f(x) = (2x-3)(x^2-4x+4) +4x -5$ or

$f (x) = 2 x^{3} - 8 x^{2} + 8 x - 3 x^{2} + 12 x - 12 + 4 x - 5$ $f(x) = 2x^3-8x^2+8x-3x^2+12x-12+4x -5$ or

$f (x) = 2 x^{3} - 11 x^{2} + 24 x - 17$ $f(x) = 2x^3-11x^2+24x-17$

A standard form of cubic equation is $f (x) = a x^{3} + b x^{2} + c x + d$ $f(x) = ax^3 + bx^2 + cx + d$ .

Here, the standard form is $f (x) = 2 x^{3} - 11 x^{2} + 24 x - 17$ $f(x) = 2x^3-11x^2+24x-17$ Where

$a = 2, b = - 11, c = 24 and d = = 17$ $a=2, b=-11,c=24 and d= =17$ [Ans]

What is the standard form of f(x)=(2x−3)(x−2)2+4x−5f(x)=(2x-3)(x-2)^2+4x-5 ?