What is the standard form of $f (x) = (x - 1) (- 2 x + 3) - {(2 x - 1)}^{2}$ $f(x)=(x-1)(-2x+3)-(2x-1)^2$ ?

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What is the standard form of $f (x) = (x - 1) (- 2 x + 3) - {(2 x - 1)}^{2}$ $f(x)=(x-1)(-2x+3)-(2x-1)^2$ ?

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Answer 1 · 2016-01-06T09:46:20

$f (x) = - 4 x^{2} + 9 x - 4$ $f(x) = -4x^2 +9x -4$

Explanation:

To get to standard form, multiply out and get rid of the brackets
$f (x) = (- 2 x^{2} + 2 x + 3 x - 3) - (2 x^{2} - 4 x + 1)$ $f(x) = (-2x^2 +2x +3x - 3) - (2x^2 -4x +1)$
$f (x) = - 4 x^{2} + 9 x - 4$ $f(x) = -4x^2 +9x -4$

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What is the standard form of $f (x) = (x - 1) (- 2 x + 3) - {(2 x - 1)}^{2}$ $f(x)=(x-1)(-2x+3)-(2x-1)^2$ ?

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Explanation:

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What is the standard form of f(x)=(x-1)(-2x+3)-(2x-1)^2 f(x)=(x−1)(−2x+3)−(2x−1)2f(x)=(x-1)(-2x+3)-(2x-1)^2 ?

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What is the standard form of $f (x) = (x - 1) (- 2 x + 3) - {(2 x - 1)}^{2}$ $f(x)=(x-1)(-2x+3)-(2x-1)^2$ ?