What is the standard form of f(x)=(x+3)(x-2)+(x-1)^2 f(x)=(x+3)(x−2)+(x−1)2?
1 Answer
Jan 17, 2016
2x^2 - x - 5 2x2−x−5
Explanation:
Expand the brackets ( using FOIL) and collect 'like terms'.
= x^2 - 2x + 3x - 6 + (x - 1 )(x - 1 )=x2−2x+3x−6+(x−1)(x−1)
= x^2 + x - 6 +x^2 - x - x + 1 = 2x^2 - x - 5 =x2+x−6+x2−x−x+1=2x2−x−5
