Question

What is the standard form of the equation of a circle with `x^2 + y^2 – 10x -4y + 13 =0`?

Answer 1

The standard form is: `(x-5)^2+(y-2)^2=16`

Explanation:

`x^2+y^2-10x-4y+13=0`

`x^2-10xcolor(red)(+25)+y^2-4ycolor(red)(+4)+13color(red)(-25) color(red)(-4)=0`

`(x-5)^2+(y-2)^2-16=0`

`(x-5)^2+(y-2)^2=16`