What is the standard form of $y= (1/5x^2-1/12)(1/3x+3/8)$ ?

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Answer 1 · 2016-03-12T10:16:59

$y=1/15x^3+3/40x^2-1/36x-3/96$

Given: $color(brown)(y=color(blue)((1/5x^2-1/12)) (1/3x+3/8)$

$color(brown)(y=color(blue)(1/5x^2) (1/3x+3/8)+color(blue)((-1/12))(1/3x+3/8))$

$y=(1/15x^3 +3/40 x^2)+(-1/36x-3/96)$

$y=1/15x^3+3/40x^2-1/36x-3/96$

What is the standard form of y= (1/5x^2-1/12)(1/3x+3/8) y= (1/5x^2-1/12)(1/3x+3/8) ?