What is the standard form of $y = (- \frac{1}{9} x + \frac{2}{27} x^{2}) (6 x - 18)$ $y= (-1/9x+2/27x^2)(6x-18)$ ?

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What is the standard form of $y = (- \frac{1}{9} x + \frac{2}{27} x^{2}) (6 x - 18)$ $y= (-1/9x+2/27x^2)(6x-18)$ ?

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Answer 1 · 2017-12-31T14:49:32

$y = \frac{4}{9} x^{3} - \frac{2}{3} x^{2} + 2 x - \frac{4}{3}$ $y=4/9x^3-2/3x^2+2x-4/3$

Explanation:

$expand factors using FOIL$ $"expand factors using FOIL"$

$\Rightarrow (- \frac{1}{9} x + \frac{2}{27} x^{2}) (6 x - 18)$ $rArr(-1/9x+2/27x^2)(6x-18)$

$= - \frac{2}{3} x^{2} + 2 x + \frac{4}{9} x^{3} - \frac{4}{3}$ $=-2/3x^2+2x+4/9x^3-4/3$

$= \frac{4}{9} x^{3} - \frac{2}{3} x^{2} + 2 x - \frac{4}{3} \leftarrow in standard form$ $=4/9x^3-2/3x^2+2x-4/3larrcolor(blue)"in standard form"$

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What is the standard form of $y = (- \frac{1}{9} x + \frac{2}{27} x^{2}) (6 x - 18)$ $y= (-1/9x+2/27x^2)(6x-18)$ ?

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What is the standard form of y= (-1/9x+2/27x^2)(6x-18) y=(−19x+227x2)(6x−18)y= (-1/9x+2/27x^2)(6x-18) ?

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What is the standard form of $y = (- \frac{1}{9} x + \frac{2}{27} x^{2}) (6 x - 18)$ $y= (-1/9x+2/27x^2)(6x-18)$ ?