What is the standard form of $y = (- \frac{1}{9} x + \frac{2}{49} x^{2}) (7 x - 18)$ $y= (-1/9x+2/49x^2)(7x-18)$ ?

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Answer 1 · 2018-04-19T09:16:08

$\Rightarrow (\frac{2}{7}) x^{3} - (\frac{667}{441}) x^{2} + 2 x$ $color(brown)(=> (2/7)x^3 - (667/441)x^2 + 2x$

$y = (- (\frac{x}{9}) + \frac{2 x^{2}}{49}) \cdot (7 x - 8)$ $y = (-(x/9) + (2x^2)/49) * (7x - 8)$

$\Rightarrow - \frac{7 x^{2}}{9} + \frac{2 x^{3}}{7} + 2 x - \frac{36 x^{2}}{49}$ $=> -(7x^2)/9 + (2x^3)/7 + 2x - (36x^2) / 49$

$\Rightarrow \frac{2 x^{3}}{7} - (\frac{7 x^{2}}{9} + \frac{36 x^{2}}{49}) + 2 x$ $=> (2x^3)/7 -((7x^2)/9 + (36x^2)/49) + 2x$

$\Rightarrow \frac{2 x^{3}}{7} - (\frac{343 x^{2} + 324 x^{2}}{441}) + 2 x$ $=> (2x^3)/7 - ((343x^2 + 324x^2)/441) + 2x$

$\Rightarrow (\frac{2}{7}) x^{3} - (\frac{667}{441}) x^{2} + 2 x$ $color(brown)(=> (2/7)x^3 - (667/441)x^2 + 2x$

What is the standard form of y=(−19x+249x2)(7x−18)y= (-1/9x+2/49x^2)(7x-18) ?