What is the standard form of y= (-10x-1)^3+(-3x+1)^2y=(−10x−1)3+(−3x+1)2?

1 Answer
Binayaka C.
Oct 24, 2017

y= -1000x^3-291x^2-36xy=−1000x3−291x2−36x

Explanation:

Standard form cubic equation is ax^3+bx^2+cx+dax3+bx2+cx+d

y= (-10x-1)^3+(1-3x)^2y=(−10x−1)3+(1−3x)2 or

y= -(10x+1)^3+(1-3x)^2 y=−(10x+1)3+(1−3x)2

y= -{(10x)^3+3(10x)^2*1+3*10x*1^2+1^3}+1-6x+9x^2y=−{(10x)3+3(10x)2⋅1+3⋅10x⋅12+13}+1−6x+9x2
[(a+b)³=a³+3a²b+3ab²+b³]

y= -(1000x^3+300x^2+30x+1)+1-6x+9x^2)

y= -1000x^3-300x^2-30x-cancel1+cancel1-6x+9x^2

y= -1000x^3-291x^2-36x [Ans]

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